5b^2-46b-40=0

Solution for 5b^2-46b-40=0 equation:

5b^2-46b-40=0

a = 5; b = -46; c = -40;
Δ = b2-4ac
Δ = -462-4·5·(-40)
Δ = 2916
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2916}=54$
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-46)-54}{2*5}=\frac{-8}{10}
=-4/5
$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-46)+54}{2*5}=\frac{100}{10}
=10
$